Q1:

Find the value of x which makes 3x^{2} + 6x  4 a minimum. 
A. 7^{}B. 4^{}C. 1^{}D. 5 
Answer 1:


Q2:

Differentiating a velocity function gives: 
A. distance^{}B. acceleration^{}C. displacement D. gradient 
Answer 2:


Q3:

The maximum value of the function 3 + 4x  x^{2 is} 
A. 2^{}B. 2^{}C. 15^{}D. 7 
Answer 3:


Q4:

Integration of a formula for velocity gives: 
A. distance^{}B. acceleration^{}C. time D. gradient 
Answer 4:


Q5:

An object is moving in a straight line. Its distance s cm from a fixed point after t seconds is given by the equation s = t^{2} + 2t  1
Calculate the velocity after 3 seconds.

A. 4 cm/s B. 8 cm/s C. 12 cm/s D. 17 cm/s 
Answer 5:


Q6:

An object with an acceleration of zero : 
A. has stopped^{}B. has constant velocity^{}C. is slowing down^{}D. is speeding up 
Answer 6:


Q7:

An object is moving in a straight line. Its distance x cm from a fixed point after t seconds is given by the equation x = t^{3}  3t^{2} + 2t + 1
Calculate the acceleration after 2 seconds.

A. 1 cm/s^{2} B. 2 cm/s^{2} C. 6 cm/s^{2} D. 12 cm/s^{2} 
Answer 7:


Q8:

What is represented by the area under a velocity/time graph? 
A. acceleration B. time C. velocity D. distance 
Answer 8:


Q9:

What is represented by the gradient at any point on a distance/ time graph? 
A. distance^{}B. velocity^{}C. acceleration^{}D. time 
Answer 9:


Q10:

An object is moving in a straight line. Its velocity v cm/s after t seconds is given by the equation v = 4t  1. If its distance from a fixed point after 1 second is 3 cm, find its distance after 2 seconds.
Calculate the acceleration after 2 seconds.

A. 6 cm B. 7 cm C. 8 cm D. 9 cm 
Answer 10:

