Differentiation gives the gradient of a curve at a particular point.

Integration has a wide range of applications incuding finding volumes, heat, mass and areas.

In earlier topics, we estimated the area under curves using the Trapezium Rule and Simpson's Rule, we now study a more precise method.

The definite integral Y12_Area_under_Curves_01.gif gives the area shaded on the right. Y12_Area_under_Curves_02.gif

Area between Curve and x-axis

To find the area between a curve, two x-values and the x-axis, as shaded in the example on the diagram below, evaluate the definite integral between those x-values.

Example

Find the shaded area between the curve f(x) = x2-6x + 10 , the lines x = 2 and x = 5 and the x-axis.

Evaluate the definite integral:

Y12_Area_under_Curves_03.gif(x2 − 6x + 10) dx

 

Y12_Area_under_Curves_04.gif

The shaded area is 6 square units.

 

Y12_Area_under_Curves_05.gif

It is advisable, although not essential to draw a diagram before carrying out the integration.

Area below x-axis

Sometimes, when the curve crosses the x-axis, part of the area may be above the x-axis and part below the x-axis.

When this happens evaluate each area separately, treating both as positive, and then add them together.

The absolute (positive) signs indicate this in the example below.

Example

Find the shaded area:

Evaluate:

Y12_Area_under_Curves_06.gif

Y12_Area_under_Curves_07.gif

Area between Two Curves

If the area between two curves is required then the following rule works well.

Area between two functions =  (top function − lower function) dx

Example

Find the shaded area between the functions 
y = x2 and y = 2x − x2.

Evaluate:

Y12_Area_under_Curves_08.gif

Y12_Area_under_Curves_09.gif