1. a.P(X = 0) = 0.0022 and P(X = 2) = 0.0425

b. P(X = 0) = 0.0025 and P(X = 2) = 0.0446. The Poisson would not really be an appropriate approximation as np > 5 and nq ≥ 5

2. 0.1725

3. 0.2936

4. A good approximation is a Poisson distribution because p is small at 0.02.

The mean for the Poisson distribution is λ =np = 10 × 0.02 = 0.2.

P(X < 2) = P(X = 0) + P(X = 1) = 0.8187 + 0.1637 = 0.9824