Find the equation of the line passing through the point (3, 4) and perpendicular to the line y = 2x + 3 The gradient of the line y = 2x + 3 is 2 Let the line perpendicular to y = 2x + 3 have a gradient of m m x 2 = -1 Using y − y1= m(x − x1) y − 4 = -0.5(x − 3) y − 4 = -0.5x + 1.5 0.5x + y − 5.5 = 0 x + 2y − 11 = 0 |