e.g. y = x + 1 ............... A
y = -2x − 2 ................B
x + 1 = -2x − 2 (equating the ys) 3x = -3 (re-arranging) x = -1
x + 1 = -2x − 2 (equating the ys)
3x = -3 (re-arranging)
x = -1
Substitute x = -1 into equation A
y = 0
The solution is ( -1, 0)
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