1.

 a. 45.6 = 4.56 × 101 b. 0.24 = 2.4 × 10-1 c. 0.032 = 3.2 × 10-2 d. 1541.7 = 1.5417 × 103 e. 843 000 = 8.43 × 105 f. 0.000 002 = 2 × 10-6

2.

a. The distance around the equator is 1.2756 × 104 kilometres.
b. The height of Mount Everest is 8.863 × 103 metres.
c. The radius of a cell is 1.8 × 10-5 millimetres.
d. The density of hydrogen is 8.71 × 10-2 grams per cubic centimetre.

3.

 a. 5.12 × 102 = 512 b. 4.1 × 10-1 = 0.41 c. 1.6 × 104 = 16 000 d. 6.1 × 106 = 6 100 000 e. 9.61 × 10 -3 = 0.00961 f. 8.3 × 10-6 = 0.0000083

4. Calculate:

 a 5⁄8 + 3⁄4 = 13⁄8 b 4⁄5 + 3⁄4 = 111⁄20 c 3⁄4 − 1⁄8 = 5⁄8 d 43⁄8 + 21⁄4 = 65⁄8 e 61⁄5 − 23⁄8 = 333⁄40 f 26⁄7 − 17⁄8 = 55⁄56 g 1⁄4 × 2⁄3 = 1⁄6 h 5⁄11 × 7⁄9 = 35⁄99 i 4⁄5 × 15⁄16 = 3⁄4 j 75⁄99 × 33⁄100 = 1⁄4 k 31⁄2 × 41⁄4 = 147⁄8 l 13⁄8 × 21⁄4 = 33⁄32 m 3⁄4 ÷ 1⁄2 = 11⁄2 n 8⁄9 ÷ 4⁄9 = 2 o 4⁄5 ÷ 2⁄3 = 11⁄5 p 31⁄2 ÷ 7⁄8 = 4 q 14⁄5 ÷ 9⁄10 = 2 r 3⁄4 ÷ 3 = 1⁄4

5.

 a 114 b 81 c 210 d 725 e 513 f 125

6. a. The new price is \$2800.

b. The new cost is \$50.63.

c. He was 188.6 centimetres tall at the end of the year.

d. The new value is \$304, 000.

e. The population of the town after the decrease is 42750.