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Q1:
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Which curve would pass through the
point (0, 1)? |
A. y = x3
B. y = (x -1)3
C. y = x3 + 1
D. y = x3 - 1 |
Answer 1:
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Q2:
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Which function would have a cubic graph?
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A. y = x(x - 3)
B. y = (x - 2)(x + 3)
C. y = x(x + 4)(x - 3)
D. y = x2 (x - 3)(x + 1)
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Answer 2:
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Q3:
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What is the y-intercept of the function
y = (x - 2)(x + 4)(x - 1)?
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A. (0. -8)
B. (0, 8)
C. (8, 0)
D. (-8, 0) |
Answer 3:
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Q4:
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What is the equation of the cubic graph above?
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A. y = (x - 2)2(x + 1)
B. y = (x - 2)(2 - x)(x + 1)
C. y = (x + 2)(2 - x)(x - 1)
D. y = (x + 2)2(x + 1)
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Answer 4:
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Q5:
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From the graph above which could be the coordinates of one of the turning points? |
A. (1.5, -6)
B. (1.5, 1)
C. (-1, 6)
D. (-1, -6) |
Answer 5:
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Q6:
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What is the equation of the function shown above?
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A. y = (x + 1)3 + 2
B. y = (x - 1)3 + 2
C. y = (x + 2)3 + 1
D. y = (x - 2)3 + 1 |
Answer 6:
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Q7:
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Which set of points lie on the curve
y = x3 + 2?
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A. {(-1, 0), (0, 2), (1, 4)}
B. {(-1, 1), (0, 2), (1, 3)}
C. {(-1, 0), (0, 2), (1, 3)}
D. {(-1, -1), (0, 2), (1, 3)} |
Answer 7:
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Q8:
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The turning points of the function above are:
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A. (2, 0) and (-1, 0)
B. (2, 0) and (4, 0)
C. (-1, 0) and (0, 4)
D. (2, 0) and (0, 4) |
Answer 8:
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Q9:
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What is the equation of the function above? |
A. y = (x - 2)2(x + 1)
B. y = (x + 2)2(x + 1)
C. y = (x + 2)2(x -1)
D. y = (x - 2)2(x -1) |
Answer 9:
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Q10:
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What is the y-intercept of the function in question 8?
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A. (2, 0)
B. (0, 4)
C. (-1, 0)
D. (4, 0) |
Answer 10:
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